- #1
karush
Gold Member
MHB
- 3,269
- 5
$\tiny{6.5.95 Kamehameha HS}$
Express y as a function of x. $\quad C>0$
$3\ln{y}=\dfrac{1}{2}\ln{(2x+1)}-\dfrac{1}{3}\ln{(x+4)}+\ln{C}$
rewirte as
$\ln{y^3}=\ln{(2x+1)^{(1/2)}}-\ln{(x+4)^{(1/3)}}+\ln{C}$
then e thru and isolate y
i think
looks like it will be ugly
Express y as a function of x. $\quad C>0$
$3\ln{y}=\dfrac{1}{2}\ln{(2x+1)}-\dfrac{1}{3}\ln{(x+4)}+\ln{C}$
rewirte as
$\ln{y^3}=\ln{(2x+1)^{(1/2)}}-\ln{(x+4)^{(1/3)}}+\ln{C}$
then e thru and isolate y
i think
looks like it will be ugly