How come violet, with the shortest wavelength, is refracted the most?

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Violet light, with the shortest wavelength, is refracted the most due to its slower speed in a medium compared to red light, which has a longer wavelength and is bent the least. The refractive index is influenced by the dielectric properties of the medium and the wavelength of light. As light enters a medium, its speed changes, affecting the angle of refraction. A deeper understanding of this phenomenon can be found in advanced texts like Griffiths' Introduction to Electrodynamics, particularly in discussions related to Maxwell's equations. This relationship between wavelength, speed, and refraction is fundamental in optics.
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Homework Statement
How come violet, with the shortest wavelength, is refracted the most in water, whereas red, with the longest wavelength, is refracted the least?
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I'm reading Usborne's Introduction to Physics, which says the following:

The wedge of water bends each different wavelength by a slightly different amount. Red has the longest wavelength and is bent the least. Violet has the shortest and is bent the most.
 
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I can give you a partial answer. The speed of light in a medium depends on the dielectric properties of medium and the wavelength of the light. The red light travels faster in the medium than the violet light, so has a lower index of refraction.

For a fuller explanation of how the wavelength and dielectric properties determine the refractive index, I would have to consult Griffiths when I get home!
 
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PeroK said:
I can give you a partial answer. The speed of light in a medium depends on the dielectric properties of medium and the wavelength of the light. The red light travels faster in the medium than the violet light, so has a lower index of refraction.

For a fuller explanation of how the wavelength and dielectric properties determine the refractive index, I would have to consult Griffiths when I get home!
Awesome, is that David J. Griffith's Introduction to Electrodynamics by any chance?
 
plaguedbyfoibles said:
Awesome, is that David J. Griffith's Introduction to Electrodynamics by any chance?
Yes. As I suspected, it's quite advanced (chapter 9) and entails satisfying Maxwell's equations for a light wave obliquely incident on the boundary between two mediums. The speed in the medium and angle of refraction depend on the wavelength.
 
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