How Do Bound Charges and Magnetization Affect Insulators?

AI Thread Summary
Bound charges in insulators result from polarization, maintaining overall electrical neutrality despite the presence of bound surface and volume charges. In magnetized objects, magnetization leads to bound surface and volume currents, which can cancel out if uniform, resulting in a net current of zero. However, if the magnetization is non-uniform, bound volume currents can exist alongside surface currents. The discussion clarifies that while the net current from bound charges may be zero in static cases, there can still be a non-zero bound current in uniformly magnetized materials. Understanding these concepts is crucial for analyzing the behavior of insulators under electric and magnetic fields.
Niles
Messages
1,834
Reaction score
0
Hi all.

I was thinking of something: Bound charges in an insulator arise because of the polarisation, so even though we have bound surface and volume charges, an insulator will still be electrically neutral.

I was trying to apply this line of though to a magnetized object. Here, the magnetization is due to bound surface- and volume currents. If the magnetization is 100% uniform, all the bound volume currents will cancel each other, and we will have a current around the edge of our object. If the magnetization is not uniform, we will have a bound volume current - in both cases, the net current is zero. And by net current I mean the current from bound volume and surface charges.

Am I corrent about this?
 
Physics news on Phys.org
What do you mean by "net current"? If you mean \int{\bf j}d^{3}r,
that is zero in any static case. But there will be a non-vanishing bound solenoid-like current in a uniformly magnetized cylinder.
 
I mean net bound current - i.e. bound volume + surface charge
 
Susskind (in The Theoretical Minimum, volume 1, pages 203-205) writes the Lagrangian for the magnetic field as ##L=\frac m 2(\dot x^2+\dot y^2 + \dot z^2)+ \frac e c (\dot x A_x +\dot y A_y +\dot z A_z)## and then calculates ##\dot p_x =ma_x + \frac e c \frac d {dt} A_x=ma_x + \frac e c(\frac {\partial A_x} {\partial x}\dot x + \frac {\partial A_x} {\partial y}\dot y + \frac {\partial A_x} {\partial z}\dot z)##. I have problems with the last step. I might have written ##\frac {dA_x} {dt}...
Thread 'Griffith, Electrodynamics, 4th Edition, Example 4.8. (Second part)'
I am reading the Griffith, Electrodynamics book, 4th edition, Example 4.8. I want to understand some issues more correctly. It's a little bit difficult to understand now. > Example 4.8. Suppose the entire region below the plane ##z=0## in Fig. 4.28 is filled with uniform linear dielectric material of susceptibility ##\chi_e##. Calculate the force on a point charge ##q## situated a distance ##d## above the origin. In the page 196, in the first paragraph, the author argues as follows ...
Back
Top