How Do Cosine and Sine Relate to Arctan in Trigonometry?

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Cosine and sine can be expressed in terms of arctan using the relationships cos(arctan x) = 1 / √(1+x²) and sin(arctan x) = x / √(1+x²). This is derived from considering a right triangle where one side is 1, the other side is x, and the hypotenuse is √(1+x²). The angle corresponding to arctan(x) has a tangent value of x, which is the ratio of the opposite side (x) to the adjacent side (1). Understanding these relationships helps clarify the connections between trigonometric functions and their inverses. This knowledge is particularly useful in physics applications involving angles and triangles.
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Why is cos(arctan x) = 1 / root(1+x^2)

and sin(arctan x) = x / root(1+x^2)?

I would greatly appreciate help. I'm studying for physics and this came up in one of the solutions. Thank you.
 
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Think of a right triangle with sides 1 and x. Now try to imagine the values of:
- The hypotenuse, and
- The sin, cos and tan of the angle next to the "1" side.
 
Well, you could show this algebraically, however:

What is arctan(x)? arctan(x) is that angle whose tan-value is x.

Now, writing x=x/1, remember that tan can be thought of as the ratio between two of the sides in a right-angled triangle.

Identify which sides these are, and see if you can deduce the results for yourself.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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