How Do Fermion Commutation Relations Affect Current Operators in 2D Spacetime?

AI Thread Summary
The discussion focuses on the computation of commutation relations for left-handed fermions in two-dimensional spacetime, specifically analyzing the current operators defined as ##J_0^\epsilon(t,x)##. In part (a), the computed commutation relation yields a result involving delta functions, indicating spatial localization effects. For part (b), the evaluation of the vacuum expectation value leads to a seemingly simplistic result as ##\epsilon## approaches zero, raising concerns about the validity of the calculations. Participants express confusion over the implications of the results and whether they align with expected physical behavior. The conversation highlights the complexities involved in handling fermionic operators and their commutation properties in quantum field theory.
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Homework Statement


Consider left-handed fermions in two spacetime dimensions ##(t,x)##: ##\psi_L=\frac{1}{2}(1-\gamma_5)\psi_D## with ##J_0^\epsilon(t,x)=\psi_L^+(x+\epsilon)\psi_L(x-\epsilon)##.

(a). Use canonical equal-time anti-commutation relations for fermions to compute
##[J_0^\epsilon(t,x),J_0^\epsilon(t,y)]##

(b). Take ##\langle 0 \mid\psi_L^+(t,x)\psi_L(t,y)\mid 0 \rangle=\frac{1}{x-y}## and evaluate
##\langle 0 \mid[J_0^\epsilon(t,x),J_0^\epsilon(t,y)]\mid 0 \rangle## and its limit for ##\epsilon \rightarrow 0##.

Homework Equations

The Attempt at a Solution



For part (a) I got ##[J_0^\epsilon(t,x),J_0^\epsilon(t,y)]=\delta^3(x-y-2\epsilon)\psi_L^+(x+\epsilon)\psi_L(y-\epsilon)-\delta^3(y-x-2\epsilon)\psi_L^+(y+\epsilon)\psi_L(x-\epsilon)##.

Using this expression means for (b) I get in the limit ##\epsilon \rightarrow 0##

##\langle 0\mid [J_0^\epsilon(t,x),J_0^\epsilon(t,y)]\mid 0 \rangle=\frac{2\delta^3(x-y)}{x-y}##

which seems a bit too easy. What's going wrong?
 
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