How Do I Approach Potential Energy and Electric Fields in Physics?

In summary, the conversation discusses finding the function V(x,y) using the given equations. The function f(x,y) is not defined, but the conversation suggests using the given picture to find V. The final solution for V is given, but the question remains about taking the derivative of V.
  • #1
notojosh
9
0


I've no idea where I need to start. please help me!
 

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  • #2
Since:

[tex]f(x,y) = (\frac{\partial V}{\partial x}, \frac{\partial V}{\partial y})[/tex]

then:

[tex]dV = dV_x + dV_y = f(x,y) dx + f(x,y) dy[/tex]

Can you integrate to find V?

AM
 
  • #3
I don't know because f(x,y) is not defined. Can you give me more tips?

Josh
 
  • #4
notojosh said:
I don't know because f(x,y) is not defined. Can you give me more tips?

Josh

It is not defined? look at your own picture!
 
  • #5
oops... Ok

I found out V=-tan^(-1)(x/y)+tan^(-1)(y/x)+C where C is arbirary constants.. And..
now what? should I take a differentiate V as the upper equation says so is that basically asking two equations are commute? ...
 

FAQ: How Do I Approach Potential Energy and Electric Fields in Physics?

What is an electric field?

An electric field is a region in space where an electric charge experiences a force. It is created by other electric charges and can be either positive or negative.

How is an electric field calculated?

The electric field is calculated as the force exerted on a charge divided by the magnitude of the charge. It is represented by the symbol E and has units of Newtons per Coulomb (N/C).

What is the relationship between electric field and potential energy?

Electric potential energy is the energy stored in an electric field due to the presence of charged particles. The higher the electric field, the greater the potential energy stored in the field.

Can an electric field exist in a vacuum?

Yes, an electric field can exist in a vacuum. In fact, light is an example of an electric field that can travel through a vacuum.

How does distance affect the strength of an electric field?

The strength of an electric field decreases as the distance from the source charge increases. This relationship follows the inverse square law, meaning that the strength of the electric field is inversely proportional to the square of the distance from the source charge.

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