How do I determine the maximum distance, that the ball moves upward, and the time for

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To determine the maximum distance a ball moves upward and the time for the upward trip while considering air resistance, one must apply the drag force equation, Fd = 0.026 * v^2, derived from the given parameters. The net force acting on the ball combines gravitational force and air resistance, expressed as Net force = m * g – Fd. This leads to the net acceleration equation, Net acceleration = 9.8 – 0.052 * v^2, which accounts for both gravity and drag. The initial net acceleration can be calculated to understand the ball's motion better. Ultimately, solving these equations will yield the maximum height and time of ascent.
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Homework Statement



I want to learn how to solve problems with air resistance.
The equation is shown at the website below.
http://en.wikipedia.org/wiki/Drag_(physics )


Example:
A 0.5 kg ball is thrown upward at 25 m/s. The density of the air = 1.3 kg/m^3. The drag coefficient = 0.8. Cross sectional area = 0.05 m^2

Fd = ½ * 1.3 * v^2 * 0.8 * 0.05
Fd = 0.026 * v^2
How do I determine the maximum distance, that the ball moves upward, and the time for the upward trip?


Homework Equations



Fd = ½ * density * velocity^2 * drag coefficient * Cross sectional area

The Attempt at a Solution



Fd = ½ * density * velocity^2 * drag coefficient * Cross sectional area
Fd = ½ * 1.3 * v^2 * 0.8 * 0.05
Fd = 0.026 * v^2

Net force = m * g – Force of air resistance
Net force = (0.5 * 9.8) – 0.026 * v^2
Net acceleration = Net force ÷ mass
Net acceleration = 9.8 – 0.052 * v^2

How do I determine the maximum distance, that the ball moves upward, and the time for the upward trip

 
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First, mg is acting against the initial motion of the ball, so it should be negative. From that it may be a good place to start to solve for the initial net acceleration of the ball. Then remember that a=dv/dt
 
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