- #1
paytona
- 11
- 0
Homework Statement
The 20.0 kg box is being pushed with a 45.0N Force acting at an angle of 25.0*. The coefficient of kinetic friction on this surface is 0.150. Find the acceleration
Homework Equations
F=ma
Fy=0
Fx=0
The Attempt at a Solution
So I attempted this so far
(sum)Fy=0
Py+Fn-Fg=0
Fn=Fg-Py
Fn=(20.0kgx9.81m/s^2)-45.0Nsin335*
Fn=215.217822N
I tried to go and do sum of all the forces on the x-axis but there's no point because we already have Ffk and Px... So now do I go ahead and put all of the forces in for Sum of F in
(sum)F=ma and solve for a?
as in would I do
Fx-Fg+Fn-Ffk=ma?