How do I simplify this equation step by step?

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The equation presented for simplification is ((20*(4*x-1)^4)/(3*x+5)^7) - ((4*x-1)^5/(21*(3*x+5)^8)). The initial approach involved factoring out (4*x-1)^4/(3*x+5)^7, leading to a new expression. After multiplying by 21(3x+5)^8, the simplification process yielded (4x-1)^4/(21(3x+5)^8)(1256x + 2101). The final expression confirms that 1256 and 2101 have no common factors, indicating that the simplification is complete. The discussion emphasizes the importance of careful manipulation to ensure the equation remains equivalent.
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Homework Statement


simplify the following equation
((20*(4*x-1)^4)/(3*x+5)^7)-((4*x-1)^5/(21*(3*x+5)^8))

The Attempt at a Solution


i took (4*x-1)^4)/(3*x+5)^7) as a common factor and ended up with

(4*x-1)^4)/(3*x+5)^7)*(20-((4*x-1)^5/(21*(3*x+5)^8)))

can someone show me how to simplify this all the way, step by step please so i know how to do it for other questions =)
 
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steve snash said:

Homework Statement


simplify the following equation
((20*(4*x-1)^4)/(3*x+5)^7)-((4*x-1)^5/(21*(3*x+5)^8))

The Attempt at a Solution


i took (4*x-1)^4)/(3*x+5)^7) as a common factor and ended up with

(4*x-1)^4)/(3*x+5)^7)*(20-((4*x-1)^5/(21*(3*x+5)^8)))

can someone show me how to simplify this all the way, step by step please so i know how to do it for other questions =)

I would multiply by 21(3x+5)^8 so

= 20(4x-1)^4\times21(3x+5) - (4x-1)^5

Then Factor out (4x-1)^4

= (4x-1)^4\times[420(3x+50)-(4x-1)]

Simplify Inside Brackets.
 
that comes out with (4x-1)^4 (1256 x+2101) which is wrong, anybody else no how to simplify this problem?
 
steve snash said:
that comes out with (4x-1)^4 (1256 x+2101) which is wrong, anybody else no how to simplify this problem?

OOOPS! My bad. You are right. I actually just multiplied the whole thing by 21(3x+5)^8 which does not equal 1 so I changed the function. Here is another try which is right (I graphed them both and they are the same) I just do not know if it is completely simplified:

\frac{20(4x-1)^4}{(3x+5)^7} - \frac{(4x-1)^5}{21(3x+5)^8}<br /> <br /> = \frac{(4x-1)^4}{(3x+5)^7}\left[20 - \frac{4x-1}{21(3x+5)}\right]<br /> <br /> = \frac{(4x-1)^4}{(3x+5)^7}\left[\frac{20*21(3x+5)-(4x-1)}{21(3x+5)}\right]<br /> <br /> = \frac{(4x-1)^4}{21(3x+5)^8}(1256x+2101)

Notice it is the same answer as before just divided by 21(3x+5)^8, so that WOULD be multiplying the function by 1 and thus not change it. Also, 1256 and 2101 do not have any common factors but 1 so that cannot be simplified more.
 
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