mblair90
- 6
- 0
1. In the circuit of the figure, find the current supplied by the battery.
2. Find the current through the 6\Omega resistor.
Attempt at a solution:
To find the total current supplied by the battery I tried:
\frac{6*4*2}{6+4+2} = 4\Omega
Then I did that resistance in series with the other:
4 + 1 = 5\Omega
Then I figured to find the current I would use I=\frac{V}{R} giving I=\frac{6}{5}. But 6/5 is not the answer for part A apparently. And I have no idea how to get part B.