- #1
mblair90
- 6
- 0
1. In the circuit of the figure, find the current supplied by the battery.
2. Find the current through the 6[tex]\Omega[/tex] resistor.
Attempt at a solution:
To find the total current supplied by the battery I tried:
[tex]\frac{6*4*2}{6+4+2}[/tex] = 4[tex]\Omega[/tex]
Then I did that resistance in series with the other:
4 + 1 = 5[tex]\Omega[/tex]
Then I figured to find the current I would use I=[tex]\frac{V}{R}[/tex] giving I=[tex]\frac{6}{5}[/tex]. But 6/5 is not the answer for part A apparently. And I have no idea how to get part B.