MHB How Do You Calculate 'n' in This Permutation Problem?

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To find 'n' in the permutation problem, the equation 1/4! + 1/5! + 1/6! = n/7! is solved by multiplying both sides by 7!. This leads to the calculation of n as 7 * 6 * 5 + 7 * 6 + 7, resulting in n = 259. The discussion suggests that the number 259 might hold a special significance, possibly as an encrypted message. The problem is deemed solvable and not impossible.
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Find 'n' using permutations:

1/4! + 1/5! + 1/6! = n/7!
 
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Arunachaleshwar said:
1/4! + 1/5! + 1/6! = n/7!

Welcome on MHB Arunachaleshwar!...

... the problem You propose is not 'impossible'... multiplying the two sides for 7! You have...

$\displaystyle n= 7 \cdot 6 \cdot 5 + 7 \cdot 6 + 7 = 259$

... can it be that You are sending an encrypted message in which the number 259 has a special meaning? ...

Kind regards

$\chi$ $\sigma$
 

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