- #1
klopez
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1. The figure below shows the drive train of a bicycle that has wheels 67.3 cm in diameter and pedal cranks 17.5 cm long. The cyclist pedals at a steady angular rate of 76.5 rev/min. The chain engages with a front sprocket 15.2 cm in diameter and a rear sprocket 7.25 cm in diameter.
2. v = r*w
3. First I tried to find the velocity of the rear sprocket.
radius of rear sprocket is 0.0363 m
angular speed of pedaling is 8.01 rad/s
v = 0.0363 * 8.01
v = .291 m/s
radius of wheels is 0.337 m
So I used the velocity of the rear sprocket to calculate the angular speed of the wheel
w = .291/.337
w = .864 rad/s
I am using WebAssign, and when I entered this answer, it said my answer differed by orders of magnitude. Any help would be greatly appreciated, since I only have one more shot at getting the answer right. Thanks
Kevin
2. v = r*w
3. First I tried to find the velocity of the rear sprocket.
radius of rear sprocket is 0.0363 m
angular speed of pedaling is 8.01 rad/s
v = 0.0363 * 8.01
v = .291 m/s
radius of wheels is 0.337 m
So I used the velocity of the rear sprocket to calculate the angular speed of the wheel
w = .291/.337
w = .864 rad/s
I am using WebAssign, and when I entered this answer, it said my answer differed by orders of magnitude. Any help would be greatly appreciated, since I only have one more shot at getting the answer right. Thanks
Kevin