How Do You Calculate the Tension in Wires Holding a Street Light?

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To calculate the tension in the wires holding a 150N street light, consider the vertical and horizontal components of the forces. The vertical components of the tensions in the wires must equal the weight of the light, while the horizontal components must cancel each other out. Use trigonometric functions, specifically sine and cosine, to resolve the forces based on the angles of 30 degrees and 45 degrees. Since the system is in equilibrium, the sum of the forces in both directions must equal zero. This approach will allow for the determination of the tension in each wire.
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A street light weighing 150N hangs from two wires as shown. One makes a 30 degree angle with the horizontal. The other makes a 45 degree angle with the horizontal. Find the tension in each wire.

(I have no clue please help!)
 
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Try thinking of the force from each wire as the sum of a vertical component and a horizontal component (you may need some sines and cosines to do this). The object isn't moving, so all of these must balance: the vertical force from the two wires is equal and opposite to the force of gravity, and the horizontal components must cancel.
 
Ohh thank u!
 
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