How Do You Derive the Volume Formula for a Cone with Variable Radius and Height?

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The discussion focuses on deriving the volume formula for a cone with variable radius and height. The participant seeks clarification on whether the provided formula, V = π/3 * (R(1 - x/2π))^2 * √(R^2 - (R(1 - x/2π))^2), is the one they need to derive. They mention using Pythagoras' theorem to relate the cone's dimensions, specifically R, r, and h. The goal is to express the volume in terms of R and determine which value of x maximizes the cone's volume. The conversation emphasizes the need for a clear derivation process to achieve this.
chris777
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I can't figure out how to derive this. This is the formula for the volume of a cone. R is a constant and the side of the cone. Can be any real number.

If anyone could take a crack at deriving this id be very greatful!

V = \pi/3 * (R(1 - x/2\pi))^2 * \sqrt{(R^2 - (R(1 - x/2\pi))^2}
 
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Is that your formula or the one you need to derive? And what exactly are you tring to derive? The formula for the volume of a cone?
 
V=\frac{\pi r^{2}h}{3}

.If the (semi)cone is rectangular (the axis joining the top and the center of the base (assumed a circle)),then u can use Pythagora's theorem

R^{2}=r^{2}+h^{2} and then can express the volume in terms of "R" and either the height "h",or the radius of the circle (the base) "r".

Daniel.
 
r = R(1-x/2pi)
h = sqrt( R^2 - ( R (1-x/2pi)))

these are put into the formula for the volume of the cone. Now I need to derive that equation to know which x will give the max volume of the cone.
 
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