How do you factor something like 8x^6+64?

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To factor the expression 8x^6 + 64, one can start by factoring out the common factor of 8, resulting in 8(x^6 + 8). The expression x^6 + 8 can be recognized as a sum of cubes, which can be factored using the formula a^3 + b^3 = (a + b)(a^2 - ab + b^2). Here, a is x^2 and b is 2, leading to the factorization 8[(x^2 + 2)(x^4 - 2x^2 + 4)]. This method effectively simplifies the original polynomial. The final factored form is 8(x^2 + 2)(x^4 - 2x^2 + 4).
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Homework Statement


I need to factor the following.
8x^6+64?

Homework Equations





The Attempt at a Solution


I really have no idea. I can pull 8 out and write 8(x^6)+64 but it doesn't get father than that.
 
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appplejack said:

Homework Statement


I need to factor the following.
8x^6+64?

Homework Equations





The Attempt at a Solution


I really have no idea. I can pull 8 out and write 8(x^6)+64 but it doesn't get father than that.
You can factor this as a sum of cubes.

Here are the formulas:

a3 + b3 = (a + b)(a2 -ab + b2)
a3 - b3 = (a - b)(a2 +ab + b2)
 
appplejack said:
I can pull 8 out and write 8(x^6)+64 but it doesn't get father than that.
If you're going to do that, pull out 8 from both terms.
 

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