- #1
karush
Gold Member
MHB
- 3,269
- 5
$$3^x-14\cdot 3^{-x}=5$$
so expanded
$$x\ln{3}-\ln 7-\ln 2 +x \ln 3=\ln 5$$
ok W|A says the answer is
$$\frac{\ln\left({7}\right)}{\ln\left({3}\right)}$$
don't see the steps how?
so expanded
$$x\ln{3}-\ln 7-\ln 2 +x \ln 3=\ln 5$$
ok W|A says the answer is
$$\frac{\ln\left({7}\right)}{\ln\left({3}\right)}$$
don't see the steps how?