How do you solve (secx)(dy/dx) = e^(y + sinx)?

dmitriylm
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Homework Statement


(secx)(dy/dx) = e^(y + sinx)


Homework Equations


None


The Attempt at a Solution


Not sure. I know I can do ln of both sides and isolate the y+sinx but then I get stuck with log^(secx)
 
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Ok, I got to (e^-y)dy = (e^sinx)(cosx)dx so I should be ok from there. Just posting in case someone is interested in the future.
 
Right. Writing the equation as sec(x) dy/dx= e^y e^{sin(x)} show that it is separable. e^{-y}dy= cos(x)e^{sin(x)}dx and both of those are easy to integrate.
 
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Hi! I am struggling with the exercise I mentioned under "Homework statement". The exercise is about a specific "greedy vertex coloring algorithm". One definition (which matches what my book uses) can be found here: https://people.cs.uchicago.edu/~laci/HANDOUTS/greedycoloring.pdf Here is also a screenshot of the relevant parts of the linked PDF, i.e. the def. of the algorithm: Sadly I don't have much to show as far as a solution attempt goes, as I am stuck on how to proceed. I thought...

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