How Does an Electric Force Alter the Energy of a Boron Nucleus?

AI Thread Summary
The discussion revolves around calculating the energy changes in a boron nucleus due to an electric force. Initially, the boron nucleus has a particle energy of 2.767e-9 J, rest energy of 7.65e-10 J, and kinetic energy of 2.002e-9 J. When an electric force does 2.4e-9 J of work on the nucleus, the new particle energy needs to be determined. The rest energy remains constant at 7.65e-10 J, while the kinetic energy will also change as a result of the work done. The focus is on understanding how the electric force impacts the total energy of the boron nucleus.
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need your help!physics homework

Homework Statement [/b]

A boron nucleus has mass 8.5e-27 kg. If its speed || is 0.961c (that is, ||/c = 0.961), what are the following values?

particle energy = 2.767e-9 J

rest energy = 7.65e-10 J

kinetic energy = 2.002e-9 J


Next an electric force acts on the boron nucleus and does 2.410-9 J of work on the particle. Now what are the following values?

particle energy = ? J

rest energy = 7.65e-10 J

kinetic energy = ? J
 
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