How Does Changing Electric Field Influence Magnetic Field in a Capacitor?

AI Thread Summary
The discussion centers on calculating the magnetic field between the plates of a parallel-plate capacitor with a changing electric field. The correct approach involves using the relationship between the changing electric field (dE/dt) and the induced magnetic field (B), specifically B = (1/2)μ₀ε₀(r)(dE/dt). Participants clarify that the variable previously misidentified as dV/dt should actually be dE/dt. The initial calculations led to confusion, but the correct formula simplifies the process significantly. Ultimately, understanding the distinction between these variables is crucial for solving the problem accurately.
GeorgeCostanz
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Homework Statement



A parallel-plate capacitor has circular plates with radius 49.0 cm and spacing 2.20 mm. A uniform electric field between the plates is changing at the rate of 1.90 MV/m/s. Find the magnitude of the magnetic field between the plates at a point 12.1 cm from the axis (entirely inside the capacitor).

Homework Equations



Ampere's Law for induced current

B(2∏r) = (μ-naught)(ε-naught)(A/d)(dV/dt)

r = .121m
μ-naught = 4∏x10^-7
ε-naught = 8.85x10&-12
d = .0022m
dV/dt = 1.9x10^6 V/(m/s)
A = ∏(.49m)^2

The Attempt at a Solution



the answer is B = 1.28x10^-12 T, but i can't seem to get that answer using my equation. i'd appreciate it if someone could direct me toward my error

thanks
 
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Hi George! :smile:

(try using the X2 button just above the Reply box :wink:)

Show us your full calculations.

(In particular, what did you get for the current through the cylinder of radius 0.121 m ?)
 
@tiny-tim

sure.

Id = [ (E\circA)/d ] * (dV/dt)

Id = [ (E\circ*(∏(.492))/.0022 ] * (1.9x106)

Id = .005765 A

i guess :smile:
 
GeorgeCostanz said:
B(2∏r) = (μ-naught)(ε-naught)(A/d)(dV/dt)

mmm … your formula seems to be correct, but I'm not getting the result of 1.28 10-12 T either :confused:
 
i got the right answer using the following equation (googled the question)

B = [ (1/2)(r)(dV/dt) ] / C2

C = 3x108 = speed of light in vacuum
dV/dt = 1.9x106
r = .121m

not sure how the 2 equations are related tho
 
ah! :rolleyes: i took your word for it instead of looking at the original question …
GeorgeCostanz said:
A uniform electric field between the plates is changing at the rate of 1.90 MV/m/s.

dV/dt = 1.9x10^6 V/(m/s)

noooo :redface: … that wasn't dV/dt, it was dE/dt ! :biggrin:

is everything clear now? :smile:

(and c2 = 1/µoεo, which btw would have have been a lot easier for you to use :wink:)
 
tiny-tim said:
ah! :rolleyes: i took your word for it instead of looking at the original question …


noooo :redface: … that wasn't dV/dt, it was dE/dt ! :biggrin:

is everything clear now? :smile:

(and c2 = 1/µoεo, which btw would have have been a lot easier for you to use :wink:)


wow I'm slow
it's a miracle I've even made it this far

so for r < R,

B = (1/2)µoεo(r)(dE/dt)

thus B = [ (1/2)(r)(dE/dt) ] / C2

guess i got mixed up with all these equations/derivations in front of me

thanks tiny-tim
 
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