How Does Dancer Movement Affect the Center of Gravity on a Dance Floor?

AI Thread Summary
The discussion focuses on calculating the center of gravity for a dance floor and three couples based on their positions. The initial y-coordinate of the center of gravity was correctly calculated as 12.34 m. However, the calculation for the new x-coordinate after one couple moves was incorrect due to an error in the reference point used for the mass of the dance floor. The correct reference point should have been adjusted to account for the couple's movement, leading to confusion in the calculations. The participant acknowledged the mistake after receiving clarification on the correct approach.
lilaznjewel
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Homework Statement


Given: A flat dance floor of dimensions ℓx =
19 m by ℓy = 23 m and has a mass of M =
1600 kg. Use the bottom left corner of the
dance floor as the origin. Three dance couples,
each of mass m = 150 kg start in the top left,
top right, and bottom left corners.
What is the initial y coordinate of the cen-
ter of gravity of the dance floor and three
couples?
Answer in units of m.

The couple in the bottom left corner moves
ℓx = 10 m to the right. What is the new x
coordinate of the center of gravity?

Homework Equations


xcm =
m1x1 + m2x2/
m1 + m2

The Attempt at a Solution



for the first part I did 1600(y-11.5)+150(y-23)+150(y-0)+150(y-23)=0
and solved for y and I got 12.34
and I got it right

my problem is I did the exact same thing for the next part just you know used the X coordinates and moved (0,0) to (10,0)
1600(x-8)+150(x-0)+150(x-10)+150(x-19)=0
I came out with 8.366
but my online homework says that answer is incorrect I don't know why isn't it basically the same question but with a different number
 
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lilaznjewel said:

Homework Statement


Given: A flat dance floor of dimensions ℓx =
19 m by ℓy = 23 m and has a mass of M =
1600 kg. Use the bottom left corner of the
dance floor as the origin. Three dance couples,
each of mass m = 150 kg start in the top left,
top right, and bottom left corners.
What is the initial y coordinate of the cen-
ter of gravity of the dance floor and three
couples?
Answer in units of m.

The couple in the bottom left corner moves
ℓx = 10 m to the right. What is the new x
coordinate of the center of gravity?


Homework Equations


xcm =
m1x1 + m2x2/
m1 + m2


The Attempt at a Solution



for the first part I did 1600(y-11.5)+150(y-23)+150(y-0)+150(y-23)=0
and solved for y and I got 12.34
and I got it right

my problem is I did the exact same thing for the next part just you know used the X coordinates and moved (0,0) to (10,0)
1600(x-8)why are you using 1600(x-8)? Shouldn't it be 1600(x-9.5)?[/color] +150(x-0)+150(x-10)+150(x-19)=0
I came out with 8.366
but my online homework says that answer is incorrect I don't know why isn't it basically the same question but with a different number
see correction above[/color]. Your method is OK, although it is a bit cumbersome.
 
omg I am so stupid. Thank you for pointing out my mistake!
 
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