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Cheery Blossom
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lewmang, u'll have to ask your physics teacher about that...
lewmang said:i don't understand what a 20K Ohm at 10 lux photocell
lewmang said:does the circuit with the photocell need a power supply or does the photocell produce a flow of electricity?
No. You need to measure the photocurrent.bigbadcityboy said:im using a photovoltaic cell, would it be ok to measure the voltage with this with a circuit with just the cell and a voltmeter?
Please read up a bit on how photocells and photodiodes work.bigbadcityboy said:surely the 'voltaic' part of photovoltaic cell means it outputs a voltage. otherwise why would it be called that?
It's one that's R-rated. Like the movies.bigbadcityboy said:whats an explicit resistor?
What's the application? What's the light source, and its intensity and directivity? How big can the detector be? Can it use light concentration? Are there other interfering IR sources in the same environment? Will you be using modulation/demodulation to reject those other IR sources?super_swifty said:where could i find a type of Light Detector suitable for detecting a infrared source from approx 2 metres away
And I'll add that I seem to remember way back somewhere in this thread that the goal was to measure the output of the detector at different distances from the source, in order to figure out how that varies with distance. (Was that this thread?) You can go ahead and measure the output voltage of the photocell, but it's not going to vary much or vary smoothly with distance. When you do a good job of measuring the photocurrent (however you end up doing it), that is when you will get a nice smoothly varying function with respect to the distance from the light source.Hootenanny said:bigbadcityboy,
Photovoltaic cells produce current not a potential difference. May I suggest you read around the subject a little, may I also suggest that you start here; http://en.wikipedia.org/wiki/Photovoltaic_cell.
And you friends will not be measuring voltage unless they are using a current to voltage converter.
~H
You talk just like my son! You aren't berkeboy in disguise just messing with me, are you?bigbadcityboy said:Big Up The Physics Masseev Wicked
The IR LED from the transmitter would be a valid source, but you will probably want to force it on instead of leaving it transmitting in code. However, keep in mind that TV remote control receivers use the "current-to-voltage" converter circuitry that hoot and I have alluded to (multiple times), and they have significant gain and AGC and decode circuitry to make it possible to operate over the several meter distances. You're not going to be able to just hook up a DVM in current mode, and see a photocurrent at an IR photodiode from an IR LED a couple meters away.Zalaras said:Would a remote controller for a TV be a suitable infrared source for this experiment? Is there going to be a significant change in the photocell output over the distance of about 1.5 metres?
An ammeter is a short circuit (in reality a low explicit resistance), so hooking it across a voltage source is looking for trouble. You will likely blow the fuse in your ammeter (or DVM's current measuring circuit). And no, you can't borrow my DVM for the experiment.bigbadcityboy said:i always thought u couldn't put an ammeter across a battery, am i wrong?
Well, I just now googled solar cell datasheet, and got a bzillion hits. I went down into one, and it had the J = xxxx mA/cm^2 type number that you are looking for. Check the hits out to see if you find what you need:bigbadcityboy said:i couldn't find any data sheets for solar cells on the digikey thing. I am assumin' itl output something in the mA range