How does Faraday's Law apply to a rotating coil in a magnetic field?

AI Thread Summary
Faraday's Law indicates that the induced electromotive force (emf) in a coil is proportional to the rate of change of magnetic flux. In the case of a rotating coil in a uniform magnetic field, the current detected by the Galvanometer is expressed as I = -NBAcos(wt) / R. The discussion highlights a common misunderstanding regarding the sine and cosine functions in the context of coil orientation at t=0, suggesting that both sine and cosine solutions can be valid depending on the initial phase. The confusion arises from differentiating the magnetic flux and applying it to the resistance to find the current. Ultimately, the correct expression for current depends on the coil's orientation at the start of the rotation.
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Homework Statement


A flat square coil of N turrns and area A is rotated at an angular velocity w in a uniform magnetic field of strength B. The rotation axis is perpendicular to the magnetic field direction. The coil is connected to a Galvonometer using suitable slip ring connectors and the total resistance in the coil and meter is R. Show that the detected current is I = -NBAcos(wt) / R

Homework Equations



Fardays 's law of induction *N
I = V/R


The Attempt at a Solution


I get I = NBAwsin(wt) / R
I don't see why i am wrong. The B field and area is uniform. So I only differentiate cos(wt) and divide the emf by R to obtain the current.

Any help or suggestions would be very welcome.
 
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Both answers can be right, depending on the orientation of the coil at time t=0. Since this isn't given in the problem, all you can say is that I ~ Cos[w(t+t0)]. If t0 = 0, you get a Cos solution, if t0=-pi/(2w), you get a Sin solution, and if t0 is something else, you get something in between.
 
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