- #1
phantomvommand
- 271
- 39
Specifically for part (i) and (ii), I get the rough idea that when the voltage of the AC source is decreasing, the capacitor can discharge to "cushion" the drop in voltage. However, I have some questions about when this occurs.
1. There is an assumption that the capacitor will be charged to maximum when the AC voltage reaches its peak. Why is this assumption (largely) true?
2. How should I solve part (iii) and part (iv)?
For part (iii), I know that the period of discharge is approximately 1/f = 0.02, and RC = 0.5.
The capacitor should have Voltage = 20(e^-0.02/0.5), and the maximum voltage is 20V. The difference of the 2 values is 0.78, which is twice the correct answer of 0.39V. (BTW I am assuming 20V is the max voltage, not the RMS value, do correct me if I'm wrong.)
For part (iv), I think I am not very clear on what "conducting" means. I took "conducting" to mean "allows current to flow through", isn't that just 50% of the time?
All help is appreciated, thank you!