How far apart are two stars resolved by a 68-cm telescope?

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To determine the separation between two stars 18 light-years away using a 68-cm telescope, the resolution is calculated using the formula Theta = (1.22 * λ) / D, where λ is 540 nm. The calculated theta value is approximately 9.69e-7 radians. Using the small angle approximation, the distance between the stars can be derived from the angular resolution. The discussion emphasizes the importance of correctly applying Rayleigh's Criterion and suggests posting detailed calculations for further assistance. Accurate calculations are crucial for obtaining the correct separation distance.
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Homework Statement


Two stars 18 light-years away are barely resolved by a 68 -cm (mirror diameter) telescope. How far apart are the stars? Assume \lambda = 540 <units>nm</units> and that the resolution is limited by diffraction.
Express your answer using two significant figures.



Homework Equations


Theta=(1.22 lambda)/diameter of the lense

9.4605284 × 10^15 meters


The Attempt at a Solution


I have no clue how to do this. I plugged the give info into the equation and got theta to equal 9.6882352941176470588235294117647e-7 then i just plugged this into the Pythagorean equation to get 559491313771834207552834.45286104
 
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Roughly from similair triangles:
lamba/D = separation/distance

The angle between the stars is 1.22lambda/D so you can work out this angle (remember is answer in radians) then you have the angle between two stars a distance away so getting the distance between them is easy.
Since the angles are small you can use the apprx theta = sin theta (in radians)
 
I have worked it out both ways and both of the answers i got were wrong
 
Remember, as mgb_phys stated, Rayleigh's Criterion expresses the angular distance in radians.

If you're still getting the incorrect answer I suggest you explicitly post how you're calculating the distance.
 
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