- #1
05holtel
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Homework Statement
A thin, 100.0 g disk with a diameter of 8.00 cm rotates about an axis through its center with 0.150 J of kinetic energy.
What is the speed of a point on the rim?
The Attempt at a Solution
1/2mv^2 = 0.15
v = 1.73m/s
I know
Vt = angular velocity x r
I am not sure how to solve foe the angular velocity