How Is a Nonlinear Equation Linearized in FEM Software?

AI Thread Summary
Nonlinear equations in FEM software can be linearized by factoring out a variable and converting the equation into a recursive form. The example provided shows a nonlinear equation Y = G^(-1) * X + a * X^3 being transformed into Y(i+1) = (G^(-1) + a * X(i)^2) * X(i+1). This process involves treating separate instances of X as different terms in a sequence, allowing for the calculation of a series of Y values based on a starting value. The linearization can be understood as using the first two terms of the Taylor series in an incremental approach. Ultimately, this method enables the convergence of the sequence to satisfy the linearized equation.
aamirmub
Messages
3
Reaction score
0
Hi,

I am trying to understand an example from a FEM software manual. The manual mentions a nonlinear equation http://aamir-pc:2080/v6.9/books/exa/graphics/exa_eqn00137.gif and this equation is linearized to obtain http://aamir-pc:2080/v6.9/books/exa/graphics/exa_eqn00152.gif .[/URL] Can anyone please explain how this has been done?
 
Last edited by a moderator:
Mathematics news on Phys.org
You need to fix your messages. The two equations don't show up.
 
The nonlinear equation is Y= G^(-1) * X + a * X^3 where G and a are constants. The linearized equation is Y(i+1) = (G^(-1) + a * X(i)^2) * X(i+1) where i and i+1 are superscripts.
 
The first thing done is factor out an "X": Y= (G-1+ aX2)X. The next thing done was convert to a recursive form by treating the separate "X"s as if they were different terms in a sequence: Yi+1= (G-1+ aXi2)Xi+1. Given a starting value, X1, you could then calculate a sequence of "Y"s. If that sequence convertes, then Y= \lim_{i\to\infty}Y^i will satisfy that equation: \lim_{i\to \infty} Y^i= (G^{-1}+ a(\lim_{i\to\infty}X^i)^2)(\lim_{i\to\infty}X^{i+1}) and, since "Xi" and "Xi+1" refer to the same sequence they both converge to the same limit, X.
 
Thank you for your reply. Is the linearization carried out using the first two terms of the taylor series in incremental form?
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
Is it possible to arrange six pencils such that each one touches the other five? If so, how? This is an adaption of a Martin Gardner puzzle only I changed it from cigarettes to pencils and left out the clues because PF folks don’t need clues. From the book “My Best Mathematical and Logic Puzzles”. Dover, 1994.
Back
Top