How is Chemical Potential Affected by Altitude in an Ideal Gas?

AI Thread Summary
The discussion focuses on how the chemical potential of a monatomic ideal gas changes with altitude. It establishes that the chemical potential at height z is μ(z) = -kT ln [V (2πmkT)3/2] + mgz, indicating that the potential energy due to altitude adds to the chemical potential. Additionally, it explores the relationship between two helium gas samples at different altitudes, concluding that the number of molecules in the higher sample is given by N(z) = N(0)e^(-mgz/kT). The conversation also touches on the methods for deriving these equations, emphasizing the importance of differentiating with respect to specific variables. Overall, the thread provides a mathematical framework for understanding the impact of altitude on chemical potential in ideal gases.
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Homework Statement



Consider a monatomic ideal gas that lives at a height z above sea level, so each molecule has potential energy mgz in addition to its kinetic energy.(a) Show that the chemical potential is the same as if the gas were at sea level, plus an additional term mgz:μ(z) = -kT ln [V (2πmkT)3/2] + mgz

[N ( h2 ) ](You can derive this result from either the definition μ = -T(∂S/∂N)U,V or the formula μ = (∂U/∂N)S,V).(b) Suppose you have two chunks of helium gas, one at sea level and one at height z, each having the same temperature and volume. Assuming that they are in diffusive equilibrium, show that the number of molecules in the higher chunk isN(z) = N(0)e-mgz/kT

Homework Equations


So, what am I attempting to show? That kinetic potential is constant? What will I differentiate with respect to?

The Attempt at a Solution

 
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μ(z) = -kT*ln[V/N * (2πmkT/h2)3/2 ] +mgz
 
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