How Is Lift Calculated Using the Bernoulli Principle for an Airplane Wing?

AI Thread Summary
Lift on an airplane wing can be calculated using the Bernoulli Principle by applying the equation P1 + (1/2)densityV1^2 = P2 + (1/2)densityV2^2. Given the air density of 1.29 kg/m^3 and speeds of 347 m/s over the top and 289 m/s under the wing, the pressure difference results in a value of 5.39 x 10^4 N/m^2. This pressure difference is then multiplied by the wing area of 84.5 m^2 to yield a lift force of approximately 4.6 x 10^6 N. The calculations confirm the application of Bernoulli's equation for determining lift. The method used for this calculation is deemed correct.
th3plan
Messages
93
Reaction score
0

Homework Statement



Find the lift in Newtons due to the Bernoulli Principle on a wing of a plane of area 84.5 m^2 if the air passes over the top and the bottom surfaces at speeds of 347m/s and 289 m/s


Homework Equations



P1+(1/2)densityV^2 =P2+(1/2)densityV^2

The Attempt at a Solution



Ok so i know the density of air is 1.29kg/m^3

so i plug into equation to get

1/2(1.29kg/m^3)(347m/s)^2= 1/2(1.29kg/m^3)(289m/s)^2

then i get answer of 5.39x10^4 N/m^2

then i use equation F=PA

and P is 5.39x10^4 N/m^2 and A is 84.5m^2

to get answer of 4.6x10^6 N

Am i correct ?
 
Physics news on Phys.org
By bernouili equation
Pa+1/2pva^2 = Pb =1/2pvb^2
1/2pvb^2-1/2pva^2 =Pa-Pb
deltaP = 1/2pvb^2-1/2pva^2
deltaP * A =Lift force
I think your method is correct
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Struggling to make relation between elastic force and height'
Hello guys this is what I tried so far. I used the UTS to calculate the force it needs when the rope tears. My idea was to make a relationship/ function that would give me the force depending on height. Yeah i couldnt find a way to solve it. I also thought about how I could use hooks law (how it was given to me in my script) with the thought of instead of having two part of a rope id have one singular rope from the middle to the top where I could find the difference in height. But the...
Back
Top