How Is the Value of 'm' Determined in Interference Equations?

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The value of 'm' in interference equations is determined as any integer, including zero, which is often used to simplify calculations. Using 'm=0' is preferred for thinner coatings because it results in lower reflectance at specific wavelengths, maintaining low reflectance across a broader range. The reflectance spectrum indicates that thinner coatings, such as 100 nm, can achieve zero reflectance at a given wavelength, like 600 nm, more effectively than thicker coatings. This approach helps in optimizing the design of optical coatings. Understanding these principles is crucial for accurately determining the thickness of materials in interference applications.
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Homework Statement


http://i.imgur.com/xrba7.png


Homework Equations


I'm using this equation to find the thickness of the polymer.

[(m+(1/2)) λ = 2nt] (where "n" is the index of refraction and "t" is the thickness )


The Attempt at a Solution



I just want to know how m is determined. I've learned everything else, but I missed the first day on which m value to use and it's always just slipped my mind whenever I'm in class or lab.

Thank you for your time.
 
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m is any integer, including zero. ehild
 
Thanks, but I'm still unsure as to why "0" is used in the solution instead of "1" or "2".
 
hyde2042 said:
Thanks, but I'm still unsure as to why "0" is used in the solution instead of "1" or "2".

First: it is easier to make a thinner coating then a thick one.

Second: The reflectance depends on the wavelength, this function is about the form R=A+Bcos(4piND/lambda) (N is the refractive index, D the thickness). If the reflectance is zero at a specific wavelength, it stays low in the broadest wavelength range when D has the smallest possible value.
The figure shows the reflectance spectrum of two coatings, one 100 nm, the other 300 nm thick. Both have zero reflectance at 600 nm.


ehild
 

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