How Is Work Calculated When a Suitcase Is Pulled Up a Ramp?

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The discussion focuses on calculating the work done on a suitcase being pulled up a ramp. The suitcase has a mass of 16.6 kg, is pulled with a force of 149 N at a 20-degree incline, and travels 3.70 m. The correct formula for work done by the pulling force is simply force multiplied by distance, as the force acts parallel to the ramp. There is also a mention of calculating the work done by friction, which is a separate aspect of the problem. The participants express frustration about the timing of the homework assignments in relation to classroom instruction.
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A luggage handler pulls a suitcase of mass 16.6kg up a ramp inclined at an angle 20.0 above the horizontal by a force of magnitude 149N that acts parallel to the ramp. The coefficient of kinetic friction between the ramp and the incline is 0.262. The suitcase travels a distance 3.70m along the ramp.

Calculate the work done on the suitcase by the force F.
I am doing
W= 149*cos(20)*3.7
=518
and its not correct
 
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How about considering the work done by friction?
 
This question just wants the work done on the suitcase regardless of friction, there is another question a couple down asking the work done on the suitcase by the friction force. I am not looking for the total work yet, just the work done on the suitcase
 
Well then the work done by F is just simply force*distance. The force,F, is already parallel to the plane.
 
I got the answer to the first question, I had my calculator in degress instead of radians, but I can't figure out the equation for
Calculate the work done on the suitcase by the friction force.

My teacher has us do the homework online before she ever teaches us, and it is for a grade. So every week our class has to go into the homework like a deer in headlights
 
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