How Long Does a Ball Take to Climb a Parabolic Ramp?

  • Thread starter Thread starter errwrsysalan
  • Start date Start date
  • Tags Tags
    Ball Ramp Rolling
AI Thread Summary
The discussion focuses on calculating the time it takes for a ball to climb a parabolic ramp defined by the equation y=(x^2)/3, starting with an initial velocity of 5 m/s. Participants explore energy conservation principles and differential equations to solve the problem, but express difficulty in finding an analytical solution. Suggestions include using definite integrals and referencing similar problems, such as objects sliding in parabolic bowls. The conversation highlights the complexity of seemingly simple physics problems and the potential need for advanced methods like Lagrangian mechanics. The thread concludes with participants agreeing to revisit the problem after further consideration.
errwrsysalan
Messages
16
Reaction score
0
1. Assume there is gravity and no external force acting on the system. A ball has an initial velocity of 5 m/s and climbs up a parabolic ramp, which is defined by y=(x^2)/3. If the ball rolls exactly along the path of ramp and energy of the ball is conserved, starting from (0,0), calculate the time taken for the ball to climb to a height of y=1.

2. Ek+Ep=Einit, Vy=||v||sin(arctan(dy/dx))

3. I made a differential equations using the formula above but the differential I got is only numerical integratable (results given by wolfram alpha). I'm looking for an easier way to solve this problem. So, guys, please help! Thanks!
 
Last edited:
Physics news on Phys.org
What did you need the trig for?
Did you start with ##\frac{1}{2}m(\dot x^2+\dot y^2) + mgy = \frac{1}{2}mu^2 : u=5,\; y=\frac{1}{3}x^2## ?
 
Simon Bridge said:
What did you need the trig for?
Did you start with ##\frac{1}{2}m(\dot x^2+\dot y^2) + mgy = \frac{1}{2}mu^2 : u=5,\; y=\frac{1}{3}x^2## ?
That seems pretty helpful! I haven't learned to use and x and y things because I'm a high school student, but I've done stage 1 college maths so I think I can cope with that. I'll give it a try! Thank you!
 
Is this a problem set for high school?
 
Well. It's not, I made this question up. It'd be nice if you can solve it using high school knowledge only though.
 
Simon Bridge said:
Is this a problem set for high school?

I'm stuck again...
 
Simon Bridge said:
Is this a problem set for high school?

I might got it.. trying now
 
Simon Bridge said:
Is this a problem set for high school?

I'm trying now, but still, can you show me how you would do it please?

Guess what. I used the formula you gave me and that ends up the same differential equation I got last time using trig, which I need to use a computer to calculate it. Can you help me?
 
Please answer the question?
 
  • #10
Simon Bridge said:
Please answer the question?
errwrsysalan said:
Well. It's not, I made this question up. It'd be nice if you can solve it using high school knowledge only though.

I answered above. Basically this is some extracurricular work.
 
  • #11
Sorry - misread.
 
  • #12
Simon Bridge said:
Sorry - misread.
It's ok. So, right now I used your formula, and it ended up exactly the same as last time I did it using trig.
I got dt/dy=0.5sqrt((3+4y)/(25y-2gy^2)) dy, which even wolfram alpha couldn't give an exact solution.
I believe there is a better way to do this. Can you show me please?
 
  • #13
... this is a specific case of an object sliding inside a parabolic bowl.
If you google for that, you'll get a bunch of examples. i.e. See attachment below.

Note: ##\dot x = v(x)## is where you get stuck.
You can do $$T = \int_0^{\sqrt 3} \frac{dx}{v}$$ ... i.e. what you were doing but as a definite integral.
The indefinite integral involves elliptical functions.

It is not unusual for quite simple-seeming setups to be very difficult to solve - or even have no analytic solutions at all.
ie. Try working out the exact equation of motion for a simple pendulum - or a puck sliding in a spherical bowl.
 

Attachments

  • #14
Simon Bridge said:
... this is a specific case of an object sliding inside a parabolic bowl.
If you google for that, you'll get a bunch of examples. i.e. See attachment below.

I'd usually reach for lagrangian mechanics.
It is not unusual for quite simple-seeming setups to be very difficult to solve - or even have no analytic solutions at all.
Try working out the exact equation of motion for a simple pendulum for example - or a puck sliding in a spherical bowl.

Thank you! No problem. I need to sleep as well. I'll have a look tomorrow.
 
Back
Top