How Long Will It Take to Heat Water in an Electric Kettle?

  • Thread starter Thread starter chawki
  • Start date Start date
AI Thread Summary
The discussion centers on calculating the time required to heat 0.85 kg of water by 20 °C in an electric kettle using a 25 Ohm resistance connected to 230 V. The specific heat capacity of water is noted as 4190 J/(kg°C), leading to a total energy requirement of 71230 J. Power is calculated using the formula P=V²/R, resulting in 2116 watts. The time to heat the water is then derived using the formula t=Q/P, yielding approximately 33.66 seconds. The solution is confirmed as correct, with a suggestion to annotate the calculations for clarity.
chawki
Messages
504
Reaction score
0

Homework Statement


In an electric kettle with good heat insulation 0.85 kg water is warmed by an electrical resistance of 25 Ohms, which is connected to a voltage of 230 V. The specific heat capacity of water is 4190 J/(kg°C)

Homework Equations


In what time will the temperature of the water rise by 20 °C?

The Attempt at a Solution


P=E/t
but here we can calculate only Q
are they the same?
 
Physics news on Phys.org
Compare the units. One is a rate, the other is an amount.
 
Power is Joules/second. Heat is Joules. One is a rate, the other an amount.
 
Yes, i was meaning Q and E
i was meaning if we can write P=Q/t anstead of P=E/t...because both Q and E are energies and joules.

This is how i solved it..
Q=m*Cp*delta T
Q=0.85*4190*20
Q=71230 J

then we calculate P
P=V2/R
P=2302/25
P=2116 watt

P=Q/t
t=Q/P
t=71230/2116
t=33.66 seconds ?
 
Forms of energy are interconvertible under the appropriate circumstances. Certainly electrically produced heat energy can be used to add heat to physical substances.
 
Is my answer and the way i have written it correct ?
 
chawki said:
Is my answer and the way i have written it correct ?

Sure. Well done. Although if you have time, you should annotate the calculations a bit to explain what it is you're calculating in each section. It's a bit like writing good computer code... imagine that someone who has never seen it before needs to understand it in a hurry.
 
Thank you gneill o:)
 
Back
Top