How many children do Person X and Y have?

AI Thread Summary
Person X and Y have an equal number of children, and the problem involves distributing 3 movie tickets among them. The probability that 2 tickets go to one person's kids and 1 ticket to the other's is given as 6/7. Using combinatorial expressions, the number of children for both is determined to be 4. The calculations confirm that the solution aligns with the probability provided. The discussion concludes with the affirmation that the correct number of children is indeed 4.
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Hi, I'd appreciate help with this problem;

Person X and Y have equal number of kids. There are 3 movie tickets. The probability that 2 tickets go to kids of one and 1 ticket goes to the kids of other is 6/7. How many kids do X and Y have?

Thanx
 
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Supposing each way of distributing the tickets is of equal probability, you can find and expression using combinatorics for the desired probability in terms of N (the number of kids). Then set the probability equal to 6/7 and solve for N.
 
sorry, but i don't see any connection between the data given and no. of kids, except that both have 2 or more kids. Could u please be more definite.
Thanx for ur help.
 
Let X have N children, and Y have N children. For starters, how many ways are there to distribute the 3 tickets among the 2N children?
 
Well, i used Baye's theorem n I'm getting the no. of children to be 4, which is correct, thank You for your help.
 
shramana said:
Well, i used Baye's theorem n I'm getting the no. of children to be 4, which is correct, thank You for your help.

Baye's theorem is not reqiured:
2(nC2)(nC1)/(2nC3)=6/7 . Solving we get, n=4.
 
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