How much heat is required to melt 104g of ice at 0°C?

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To melt 104 grams of ice at 0°C into water at the same temperature, the latent heat of fusion is required, which is 3.33 x 10² J/g. The total heat needed can be calculated by multiplying the mass of the ice by the latent heat of fusion. In this case, 104 grams of ice would require 34,632 Joules of heat. The discussion highlights the importance of understanding phase changes and the application of the latent heat formula. The original poster ultimately resolved their question independently.
coey
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Hi again..

i've been working on my prelab for my physics lab, I've pretty much solved everything except for this last problem, if anyone could help me out, it'd be appreciated

thanks

Q1.

How much heat is needed for 104 grams of ice at 0° to melt into 0° water? The latent heat of fusion for ice is 3.33*105 J/kg or 3.33*102 J/g.
 
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I'd hate to just give you a formula without seeing what you've tried. All of the heat is used in the phase change: the latent heat of fusion tells you how much heat is required to melt a given amount of ice. You are told how much ice you have. Does that make sense?
 
nevvver mind i got it... i don't even know why i asked it in the first place, thanks anyway though!
 
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