How Much Power Is Required to Accelerate a Box with Friction Involved?

AI Thread Summary
To calculate the power required to accelerate a 5.0 kg box from 2.0 m/s to 8.0 m/s in 1.8 seconds with a coefficient of friction of 0.220, the net force must be determined by subtracting the frictional force from the applied force. The frictional force can be calculated using the coefficient of friction and the normal force. The work done (W) is then calculated using the net force (Fnet) and the distance moved during acceleration. The power (P) is found by dividing the work by the time taken. Understanding how to incorporate the coefficient of friction into the calculations is crucial for determining the correct net force and ultimately the power required.
BEANTOWN
Messages
5
Reaction score
0

Homework Statement



A 5.0 kg box is sliding across the floor at 2.0 m/s when it is accelerated to 8.00 m/s in 1.8 s. If the coefficient of friction is .220 how much power is required to accelerate the box?

m = 5.0 kg vi= 2.0 m/s vf = 8.00 m/s change in time = 1.8 s coefficient = .22

Homework Equations



Power = Work (W) / change in time (t)
W= Fnetd

Fnet = ma

The Attempt at a Solution


P= w/ t

w= FNetd

Heres my issue. I know Fnet(net force) = ma, which i can easily calculate. The problem is where do i use the coefficient of friction they gave me. Do I need to use it, if i already have Fnet?
 
Physics news on Phys.org
You find the force acting against the box and take that away from the force required to accelerate the box to get the net force.
 
Last edited:
So what do i use for the w= Fnetd calculation?
 
F(net)=F(applied)-F(friction)
D= distance the box moved after acceleration
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top