How Much Runway is Needed for a Plane Towing Two Gliders to Take Off?

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The discussion revolves around calculating the minimum runway space needed for a transport plane towing two gliders, given a maximum tow force of 12,000 N and each glider weighing 700 kg. The initial calculations suggested a runway length of only 20 meters, which was deemed unrealistic. A participant pointed out that the original poster had neglected to square the time value in their final calculation. After correcting this error, the revised minimum runway requirement was determined to be approximately 93 meters. The conversation highlights the importance of careful calculations in physics problems.
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A transport plane has two gliders tied behind it. The max force allowable on the tow rope is 12000N. The mass of each glider is 700kg. A velocity of 40 m/s is required to take off. What is the minimum runway space required.


The solution I have arrived at doesn't seem correct, hopefully someone can tell me where I have strayed off the path.

F = ma

12000 = (700+700)a
a = 12000/1400
a = 8.57 m/s^2



V = V(init) +at

40 = 0 +8.57t
t = 40/8.57
t = 4.67s



S = 1/2(a)t^2+V(init)t + S(init)

1/2(8.57)(4.67^2) + 0 + 0 = 20 meters


I don't think the plane could reach 40 m/s in 4.67 seconds and it would have to be a really small transport plane to take off in 20 meters. Hopefully someone can point out where I went wrong.

Thanks for the help.
 
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You forgot to square the 4.67 value. It should be about 93m

4.67s does seem a bit short, but 93 m seems ok!
 
Huh, After checking my work a few times I still missed that one. Thanks!
 
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