How Much Work Is Done When Pulling a Sled 1 km with a 45-Degree Rope Angle?

  • Thread starter Thread starter zackf
  • Start date Start date
  • Tags Tags
    Freshman
AI Thread Summary
To calculate the work done pulling a sled with a 45-degree rope angle over 1 km, the relevant equation is W = F x D. The sled has a mass of 60 kg and a friction force of 20 N, which must be considered in the calculations. Participants emphasize the importance of showing initial work and free body diagrams to receive assistance. Clarification is provided regarding terminology, noting that "Physician" refers to a medical doctor, not a physicist. Understanding these concepts is crucial for solving the problem effectively.
zackf
Messages
1
Reaction score
0

Homework Statement


A loaded sled is pulled by means of a rope that makes an angle of 45 degrees with the horizontal. The mass of the sled is 60 kg, and the friction force is 20 N. How much work is done pulling the sled along a level road for a distance of 1 km?


Homework Equations


W=FxD



The Attempt at a Solution

 
Physics news on Phys.org
Welcome to the PF, Zack. An important rule here is that we do not do your work for you and just solve your problem. You must show your own work so far to get help. What does your free body diagram look like? What equations have you been using so far?

(As an aside, generally the term "Physician" like you used in your title means a medical doctor, not a physicist. I'm not sure exactly what you meant by the use of the word. No big deal -- I just wanted to be sure you understood the distinction if english is not your primary language.)
 
Thread 'Minimum mass of a block'
Here we know that if block B is going to move up or just be at the verge of moving up ##Mg \sin \theta ## will act downwards and maximum static friction will act downwards ## \mu Mg \cos \theta ## Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Back
Top