How to Calculate the Speed of a Block Released from a Spring

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In summary, the problem involves a block with a mass of 1.20 kg and a spring with a force constant of 2.20 N/m. When the block is released, the spring pushes it and expands a distance of 0.420 meters. The floor is frictionless. The goal is to find the speed of the block as it leaves the spring. The correct equations to use are the elastic energy equation, Ue = 0.5kd^2, and the energy in a block-spring system equation, E = 0.5kx^2 + 0.5mv^2. The mistake in the attempt at a solution was using the same equation for both initial potential energy and final kinetic energy
  • #1
robertmatthew
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Homework Statement


A block of mass 1.20 kg is placed in contact with a spring with a force constant of k = 2.20 N/m. When released, the spring pushes the block and expands a distance of 0.420 meters. If the floor is frictionless, the speed of the block as it leaves the spring is ? m/s.


Homework Equations


Elastic energy is Ue = .5kd2
Energy in a block-spring system is E = .5kx2 + .5mv2


The Attempt at a Solution


Well the problem is I haven't been able to get anywhere, because in my obviously incorrect thinking, if the block has yet to be released, then all the energy is potential, so E = Ue, but if E = Ue, then .5kx2 = 0, which can't be right. So, in short, I really don't know what I'm doing here. Am I using the wrong equations or something?
 
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  • #2
robertmatthew said:

Homework Statement


A block of mass 1.20 kg is placed in contact with a spring with a force constant of k = 2.20 N/m. When released, the spring pushes the block and expands a distance of 0.420 meters. If the floor is frictionless, the speed of the block as it leaves the spring is ? m/s.


Homework Equations


Elastic energy is Ue = .5kd2
Energy in a block-spring system is E = .5kx2 + .5mv2


The Attempt at a Solution


Well the problem is I haven't been able to get anywhere, because in my obviously incorrect thinking, if the block has yet to be released, then all the energy is potential, so E = Ue, but if E = Ue, then .5kx2 = 0, which can't be right. So, in short, I really don't know what I'm doing here. Am I using the wrong equations or something?
Wecome to PF!
When the block is not yet released, the spring is compressed by 0.420 m. So its initial PE is not 0.
 
  • #3
I just solved it, but I think my problem was that I was calculating the initial potential energy while also calculating the final kinetic energy, but still using E = PE, so I ended up with zero on one side and .5mv^2 on the other. I'm not really sure why I did Kf and Ui at the same time, I guess I'm having an off day, haha. But thank you!
 

FAQ: How to Calculate the Speed of a Block Released from a Spring

What is the definition of energy?

Energy is defined as the ability to do work or cause a change in an object's motion.

How is energy related to work?

Energy and work are closely related, as work is the transfer of energy from one form to another.

What is a spring problem and how does it relate to energy and work?

A spring problem is a physics problem that involves the use of Hooke's law to calculate the force, displacement, and energy of a spring. The energy stored in a spring is related to the work done on the spring by an external force.

What is Hooke's law and how is it used in spring problems?

Hooke's law states that the force exerted by a spring is directly proportional to the distance it is stretched or compressed from its equilibrium position. This law is used in spring problems to calculate the force and displacement of a spring.

How can energy and work be calculated in a spring problem?

In a spring problem, the potential energy stored in the spring can be calculated using the formula U = 1/2kx^2, where k is the spring constant and x is the displacement of the spring. The work done on the spring can be calculated using the formula W = Fd, where F is the force applied to the spring and d is the distance the spring is compressed or stretched.

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