How to Convert a Cross Section from GeV2 to Barn | Helpful Tips

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In summary, the conversation discusses the conversion of a cross section from units of GeV^2 to barn and the use of natural units. The conversion factor needed is \hbar c = 200 MeV fm or equivalently, (\hbar c)^2 = 0.389 GeV^2 mbarn. It is suggested that for beginners, it is helpful to carry along the units until they gain more experience with the calculations. However, using natural units can also be a useful and more intuitive approach.
  • #1
maani
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Hi I have computed a cross section to 10-6 GeV2. Now I have to convert it to barn, but don't know how. Can anybody help me? Is it ok to have a cross section in units of GeV2 or is my result completely wrong?
Thanks!
 
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  • #2
You made a mistake somewhere. It should be 1/GeV2.

The conversion factor you need is [itex]\hbar c[/itex] = 200 MeV fm.
 
  • #3
Vanadium 50 said:
[itex]\hbar c[/itex] = 200 MeV fm.
Equivalently, [itex]\left(\hbar c\right)^{2}=0.389\text{ GeV}^2\text{mbarn}[/itex]
 
  • #4
If you're doing quantum gravity, then:

GeV^2 = 1.752*10^(-80) barn
 
  • #5
Count Iblis said:
If you're doing quantum gravity, then:

GeV^2 = 1.752*10^(-80) barn
It seems to me confusing in the context of the original question to hide [itex]\hbar[/itex] and c. Vanadium 50's and my result are on the first page of the particle data group booklet or review, so I think we were justified not to give further details (unless requested). I'd like to request a clarification about your formula. It seems to me, energy and length have inverse dimension for instance. Can you please re-establish the proper [itex]\hbar[/itex], c and (probably) G factors ?
 
  • #6
humanino said:
It seems to me confusing in the context of the original question to hide [itex]\hbar[/itex] and c. Vanadium 50's and my result are on the first page of the particle data group booklet or review, so I think we were justified not to give further details (unless requested). I'd like to request a clarification about your formula. It seems to me, energy and length have inverse dimension for instance. Can you please re-establish the proper [itex]\hbar[/itex], c and (probably) G factors ?

Well, I agree that the OP really meant GeV^(-2) and agree with your answers. Now, if you put G = 1, then of course, any power of GeV could be a cross section (because you've made physics dimensionless).

Now, I don't work in particle physics so, I don't have the conversion factors in my head. So, what I always do is use a few well known formulae that contain hbar, c and G to do the conversion.

To convert GeV^2 to a cross section, you can use that in General Relativity, mass and length have the same dimensions (if you put c = G = 1). So, GeV^2 is already a cross section and no additional conversion using hbar needs to be performed.

To restore G and c, we just hijack the formula for gravitational potential energy, so:

m^2 G/r = energy = m c^2

this is a dimensionally correct expression, that doesn't need to make sense. So, we have:

m G/(c^2 r) = dimensionless

Or:

E G/(c^4) = length

where E is an energy. So, we see that:

cross section = E^2 G^2/c^8


If you know the formulas for Planck length, Planck energy etc. etc., you can do the conversion directly. To convert GeV^n to a cross section, you simply divide this by the Planck energy to the power n and multiply by the Planck length squared.
 
  • #7
I think this is singularly unhelpful.

We have someone who is doing their first calculation - we know this, because they are having unit problems. Suggesting they start popping Planck masses in until the units come out right is not going to help them get the right answer. It's simply the wrong thing to do.
 
  • #8
Thanks to all of you for the fast answers. This was really my first computation and it was completely wrong. I am still working on it. But i have learned at least how to convert the units.
 
  • #9
It's very smart to carry along the units, at least until you gain more facility with these calculations. People will say, "who cares if you drop an hbar or a c", but I would respond, "but who knows what else you dropped?" Then later when you get more experience, taking the shortcut becomes more reasonable.
 
  • #10
Vanadium 50 said:
I think this is singularly unhelpful.

We have someone who is doing their first calculation - we know this, because they are having unit problems. Suggesting they start popping Planck masses in until the units come out right is not going to help them get the right answer. It's simply the wrong thing to do.

It is very unhelpful to keep students indoctrinated in the wrongful use of units. Students learn units the wrong way in high school and even at university, the false myth of the meaning of units is promoted, to the detriment of science. Then what you see is that advanced university level students are struggeling with what should be a trivial high school physics exercise.

Even many professional physicisist do not understand units as
http://arxiv.org/abs/hep-th/0208093" . :mad:
 
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  • #11
Vanadium 50 said:
It's very smart to carry along the units, at least until you gain more facility with these calculations. People will say, "who cares if you drop an hbar or a c", but I would respond, "but who knows what else you dropped?" Then later when you get more experience, taking the shortcut becomes more reasonable.

It's not just a shortcut, natural units are a bona fide unit system. The conversion back to SI units is very simple. With some minor practice, the chances of making mistakes are much less likely if you use natural units than if you use SI units.

The constants c, hbar, G, k_b, etc. etc. are nothing more than irrelevant conversion factor. Then, if we intend to use SI units when actually inserting numbers in the equation, we should make sure the correct conversion factors are present in the final result. But it can be extremely cumbersome to derive the equation with the conversion factors already present in the intermediary steps.

It is a bit like the complicated formulas frequently used by engineers were e.g. pressure appears in different ways, e.g. in atmospheres and in mm Hg. Then the formula also contains a conversion factor which has exactly the same interpretation as c, hbar, G, k_b etc.
 
  • #12
Count Iblis said:
It is a bit like the complicated formulas frequently used by engineers were e.g. pressure appears in different ways, e.g. in atmospheres and in mm Hg.
Not really. Keeping track of the powers of mass is quite a useful consistency check. I'd say it helps to avoid errors. Anyway, unless the original posters intends to go into quantum gravity, in which case this is not the appropriate sub-forum, advising him to overlook all dimensions together is certainly not very pedagogical. First he should learn the dimensions of the various fields, like spinors/vectors etc... at the very least.
 
  • #13
Yes, I agree that it's useful to keep track of the powers of the mass. But then you can put hbar = c = 1. The fact that inverse mass is a length should be common knowledge. Even I know that and I don't work with this stuff on a daily basis.
 
  • #14
Count Iblis said:
Yes, I agree that it's useful to keep track of the powers of the mass. But then you can put hbar = c = 1. The fact that inverse mass is a length should be common knowledge. Even I know that and I don't work with this stuff on a daily basis.
When I said power, I meant both positive and negative. That's indeed what we do all the time. The problem comes about with m^2 G/r=E and setting G=1. With an arbitrary number of hidden G factors, you loose the ability to check the number of powers of mass (or energy, or length, or time) on both sides of the equation. For instance, with
cross section = 1/(E^2)
 
  • #15
humanino said:
When I said power, I meant both positive and negative. That's indeed what we do all the time. The problem comes about with m^2 G/r=E and setting G=1. With an arbitrary number of hidden G factors, you loose the ability to check the number of powers of mass (or energy, or length, or time) on both sides of the equation. For instance, with
cross section = 1/(E^2)

Indeed, but then, you're not going to set G = 1 in ordinary QFT computations. And if one contemplates a fundamental theory, then one has to be reasonble and accept the fact that Nature may be fundamentally dimensionless.

If you formulate some lattice statistical mechanics model, like the Ising model, you only have pure numbers. But close to the critical temperature you can look at some scaling limit in which you can formulate hte model as some effective field theory. The correlation length then enters the effective theory as an inverse mass.

Cardy writes in one of his books that the Renormalization Group is simply a sophisticated way of doing dimensional analysis. :smile:
 

Related to How to Convert a Cross Section from GeV2 to Barn | Helpful Tips

1. How do I convert a cross section from GeV2 to Barn?

The conversion from GeV2 to Barn is a unit conversion used in particle physics to convert the unit of cross section measurement from GeV2 to barn. It is usually done to make measurements more manageable and easier to compare. The conversion factor is 10^-28, meaning that 1 GeV2 is equal to 10^-28 barn.

2. Why is it necessary to convert a cross section from GeV2 to Barn?

Cross sections are typically measured in units of GeV2 in particle physics experiments. However, barn is a more commonly used unit in nuclear and particle physics. Converting to barn allows for easier comparison and understanding of cross section measurements.

3. How do I apply the conversion factor of 10^-28 when converting from GeV2 to Barn?

To convert from GeV2 to barn, simply multiply the measurement in GeV2 by the conversion factor of 10^-28. For example, if the cross section is 5 GeV2, the conversion to barn would be: 5 GeV2 * 10^-28 = 5 * 10^-28 barn = 5 * 10^-28 * 1 barn = 5 * 10^-28 barn.

4. Are there any other units used for cross section measurements besides GeV2 and Barn?

Yes, there are other units used for cross section measurements, such as millibarn (mb) and femtobarn (fb). These are also commonly used in particle physics experiments and have their own conversion factors to GeV2.

5. Can I convert a cross section from Barn to GeV2?

Yes, the conversion can be done in reverse by dividing the measurement in barn by the conversion factor of 10^-28. For example, if the cross section is 2 barn, the conversion to GeV2 would be: 2 barn / 10^-28 = 2 * 10^28 GeV2 = 2 * 10^28 * 1 GeV2 = 2 * 10^28 GeV2.

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