MHB How to Expand Algebraic Identities

  • Thread starter Thread starter NotaMathPerson
  • Start date Start date
  • Tags Tags
    Identity
AI Thread Summary
To expand algebraic identities effectively, start by multiplying out the brackets on both sides of the equation to check for equivalence. It's recommended to first expand the right-hand side, as this can reveal cancellations that simplify the process. The identity (m + n)² = m² + 2mn + n² is a useful reference for expansion. Additionally, the expansion of the product (w+x)(y+z) can be applied to further simplify the expression. Following these steps should help in achieving the desired form of the equation.
NotaMathPerson
Messages
82
Reaction score
0
Hello! Please help me start solving this.

View attachment 5567

I did expand the lhs but I still can't make it to be like the rhs. Any help would be appreciated!
 

Attachments

  • ALGEBRA.jpg
    ALGEBRA.jpg
    12.2 KB · Views: 104
Last edited:
Mathematics news on Phys.org
There may be neater ways to do this, but you can't go wrong if you simply multiply out the brackets on both sides and see whether they give the same answer.
 
Hint: expand the right-hand side, first. You'll find some stuff "cancels".
 
According to Opalg, you probably know (m + n)² = m² + 2mn + n².
Also, $$(w+x)(y+z)=wy+xy+wz+xz$$.
Therefore, $$(wy+xy+wz+xz)(\alpha+\beta)=\alpha wy+\alpha xy+\alpha wz+\alpha xz+\beta wy+\beta xy+\beta wz+\beta xz$$.
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
Back
Top