Automotive How to find "equivalent stiffness" of the suspension system?

AI Thread Summary
To find the equivalent stiffness (k') and damping (c') of a suspension system, potential energy methods can be applied, combining spring energies while considering springs in series as resistors in parallel. The potential energy can be expressed as V=k(eq)*x^2, leading to a formulation involving k terms. Damping factors are often overlooked in stiffness calculations, complicating the integration of dampers into the analysis. An alternative approach involves creating a free body diagram (FBD) of the masses and applying Laplace transforms to derive transfer functions. Additional resources, such as supplemental notes on equivalent viscous damping, may provide further insights into the topic.
yunias
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Dude i have a problem to find the equivalent stiffness (k') and damping (c') of this equation ? thank youvery much physics forum
 

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You may want to look into potential energy methods
 
You add up and combine all of the spring energies taking into account springs in series act like resistors in parallel, then you factor out your x or theta if its rotational isolating the stiffnesses. Potential energy V=k(eq)*x^2

You'll end up with something like V=( terms with k )*x^2
 
Not sure how to factor dampers into a stiffness i feel like they would be ignored

Only other thing i know to do is to write out the fbd of your masses and the middle section on the 2nd image, laplace transform the system equations and get the transfer functions but I'm not sure if that helps you
 

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