How to Find Inverse of a Matrix

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    Inverse Matrix
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Finding the inverse of a matrix can be complex and time-consuming, often requiring methods like row reduction or Gauss elimination with back substitution. While row reduction is considered straightforward, some prefer using the transpose of the matrix of cofactors divided by the determinant, despite it being more calculation-intensive. Estimating the inverse is also a common practice for achieving reasonable accuracy without the need for exact calculations. Tools like Excel can simplify the process for specific matrix sizes. Ultimately, understanding multiple methods can enhance problem-solving flexibility in matrix inversion.
nanoWatt
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Hi,

I'm taking a Calculus I class, so they won't be going into Matrices very much. That's more for Linear Algebra.

I'm going through an E&M book now (as a refresher from my Physics days of 7 years ago). This book assumes knowledge in getting the inverse of a matrix.

Using this site, I was able to find the inverse, by using row reduction. However, I was wondering if there is a quicker or easier way to find a matrix inverse.

http://people.hofstra.edu/Stefan_waner/RealWorld/tutorialsf1/frames3_3.html
 
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Be aware that finding the inverse can be a very long and laborious task. In fact, much of the time this is simply not done, and the inverse is either estimated, which can be done fairly easily to a reasonable degree of accuracy, or else ways around getting the inverse are used, e.g. gauss elimination followed by back substitution.
 
There are a number of different ways of finding an inverse matrix. In my opinion, "row reduction" is the simplest.
 
Another way is to use the fact that the inverse of A is the transpose of the matrix of cofactors of A divided by the determinant of A. Probably more calculations than row reduction, but I find it easier to remember. And for a given size matrix, it's pretty easy to program in Excel.
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...

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