How to modal a voltage gradient from a single cylinder

AI Thread Summary
To model the voltage gradient from a single conducting cylinder with an applied voltage and no current, the challenge lies in the unknown charge density. The standard voltage equation for a uniform cylinder is V(r) = (-q/2 Pi ep0) Ln(r/R0) + V0, but without knowing the charge density (q), it complicates the modeling. Unlike spheres, where capacitive formulas can substitute easily, cylinders lack a straightforward capacitive equation for this scenario. The discussion focuses on finding a way to eliminate or replace the charge term with a numerical value to accurately represent the voltage gradient outside the solid cylinder. Clarification on these modeling techniques is essential for effective analysis.
Wondering
Messages
4
Reaction score
0
Hello,

I am a bit trumped. I know how to calculate the voltage of a single uniform cylinder:

V(r) = (-q/2 Pi ep0) Ln(r/R0) + V0

q: Charge density
r: radius from outside of the cylinder. r >= R0
R0: radius of the uniform cylinder
V0: applied voltage to the cylinder

Here is my problem. How do I modal this given that I do not know the charge density. I will simply have a conducting cylinder with a voltage applied to it and no current will be flowing.
This can be done for a sphere because I can use the capacitive formula of a sphere and substitute. But the cap. equation for a cylinder does not allow a single cylinder.

Let me know.
 
Physics news on Phys.org
I am referring to the voltage gradient outside of the solid cylinder. I need to know how to remove the charge term or replace it with a numerical value.
 
Susskind (in The Theoretical Minimum, volume 1, pages 203-205) writes the Lagrangian for the magnetic field as ##L=\frac m 2(\dot x^2+\dot y^2 + \dot z^2)+ \frac e c (\dot x A_x +\dot y A_y +\dot z A_z)## and then calculates ##\dot p_x =ma_x + \frac e c \frac d {dt} A_x=ma_x + \frac e c(\frac {\partial A_x} {\partial x}\dot x + \frac {\partial A_x} {\partial y}\dot y + \frac {\partial A_x} {\partial z}\dot z)##. I have problems with the last step. I might have written ##\frac {dA_x} {dt}...
Thread 'Griffith, Electrodynamics, 4th Edition, Example 4.8. (Second part)'
I am reading the Griffith, Electrodynamics book, 4th edition, Example 4.8. I want to understand some issues more correctly. It's a little bit difficult to understand now. > Example 4.8. Suppose the entire region below the plane ##z=0## in Fig. 4.28 is filled with uniform linear dielectric material of susceptibility ##\chi_e##. Calculate the force on a point charge ##q## situated a distance ##d## above the origin. In the page 196, in the first paragraph, the author argues as follows ...
Back
Top