- #1
manish00333
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Solve sin2x= sqrt(2)/2 (using algebra)
the interval is between 0 and 2pi
i got the first two answers: pi/8 and 3pi/8, but i don t understand how to get the other two: 9pi/8 and 11pi/8.
thanks!
the interval is between 0 and 2pi
i got the first two answers: pi/8 and 3pi/8, but i don t understand how to get the other two: 9pi/8 and 11pi/8.
thanks!
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