Hydrogen atom: potential well and orbit radii

shallowbay
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Hello,

I happened to open up an old book by Sah, and in it he says:

"it is evident that the electron orbit radius is half the well radius at the energy level E_n"

The orbit radius is r_n=\frac{4*\pi*ε_0*\hbar^2*n^2}{mq^2} and the potential well V(r_n)=\frac{-q^4*m}{(4*\pi*ε_0)^2*\hbar^2*n^2}

Of course the orbit radius has to be confined in the well, but it's not obvious to me why it should be exactly half the well radius? This isn't something I recall seeing before either.

Thanks
 
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What does "well radius" even mean in this context? I've never seen anyone talk of the "radius" or "width" of a 1/r potential well; it extends from r = 0 to r = ∞.
 
He's speaking of the width of the potential well due to the nucleus at the specific energy levels E_n. So that apparently r_1 of the electron is half of the width of the potential well itself at E_1, or the well would be twice the Bohr radius.

Attached diagram he uses where he has drawn the orbit radius to be half that of the well. When I just add it to the post it is far too small to be useful.
 

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