MHB I.7 verify that the given function is a solution

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$\textsf{i.7 verify that the given function is a solution} $
\begin{align*}\displaystyle
u_{xx}+u_{yy}+u_{zz}&=0\\
u=\phi(x,y,z)&=(x^2 + y^2 +z^2)^{-1/2}\\
(x,y,z)&\ne(0,0,0)
\end{align*}

ok there is no book answer:mad:
$\tiny{Elementary \, Differential \, Equations \, Boundary \, Value \, Problems \quad Boyce/Diprinaia \quad 1965}$
 
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karush said:
$\textsf{i.7 verify that the given function is a solution} $
\begin{align*}\displaystyle
u_{xx}+u_{yy}+u_{zz}&=0\\
u=\phi(x,y,z)&=(x^2 + y^2 +z^2)^{-1/2}\\
(x,y,z)&\ne(0,0,0)
\end{align*}

ok there is no book answer:mad:
$\tiny{Elementary \, Differential \, Equations \, Boundary \, Value \, Problems \quad Boyce/Diprinaia \quad 1965}$

So evaluate those derivatives and see if they combine in that way to give 0...
 
Prove It said:
So evaluate those derivatives and see if they combine in that way to give 0...

ok I am like page 5 in the book so I don't know exactly what $U_{xx}$ means I presume it means 2nd derivative of the function U
 
That notation usually means the second partial derivative w.r.t $x$.
 
so what would we use for a function?
 
karush said:
so what would we use for a function?

$$u=\phi(x,y,z)=\left(x^2 + y^2 +z^2\right)^{-\Large\frac{1}{2}}$$
 
There is the following linear Volterra equation of the second kind $$ y(x)+\int_{0}^{x} K(x-s) y(s)\,{\rm d}s = 1 $$ with kernel $$ K(x-s) = 1 - 4 \sum_{n=1}^{\infty} \dfrac{1}{\lambda_n^2} e^{-\beta \lambda_n^2 (x-s)} $$ where $y(0)=1$, $\beta>0$ and $\lambda_n$ is the $n$-th positive root of the equation $J_0(x)=0$ (here $n$ is a natural number that numbers these positive roots in the order of increasing their values), $J_0(x)$ is the Bessel function of the first kind of zero order. I...
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