If bar A moves right at a speed of x,how does bar B move?

[zizodev]

Hi..

Homework Statement

http://data.imagup.com/12/1146557882.jpg
If bar A moves right at a speed of x,how does bar B move?

Homework Equations

speed of the gear(A) * number of teeth(A) =speed of the gear(B) * number of teeth(B)

The Attempt at a Solution

as A slide to the right, so the C gear will turn Clockwise (CW);the D Anti CW ,E CW;
F anti CW so B will slide to the right.
about the spped the B will slide slower than rank A :)
thnks in advance.

 

[tiny-tim]

hi zizodev!

yes, that's fine

quicker wold be to count the number of gears …

the are 4 circular gears, and 4 is even, so the first must go the opposite way to the fourth

(and yes, B will slide to the right, slower than A … you still need to count teeth to find how much slower! )

 

[zizodev]

yes tiny-tim that's right...and the value is X/2 since the speed of the A=X.:)

 

[tiny-tim]

yup!

 

[asteriatic]

Based on the image provided, it looks like bar B is connected to gears C, D, E, and F. Since bar A is moving to the right, the gears connected to it (C, D, E, and F) will also rotate in the same direction. This means that bar B will also move to the right, but at a slower speed than bar A. This is because the gears connected to bar B have different numbers of teeth than the gears connected to bar A, which will affect their rotational speeds. The equation you provided is correct and can be used to calculate the exact speed of bar B based on the speed of bar A and the number of teeth on the gears.