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bhobba said:It is not in a superposition of states after decoherence - it is in a mixed state - which is different.
Check out:
ftp://orthodox-hub.ru/ftp2/books/_%D4%E8%E7%E8%EA%E0_%CC%E0%F2%E5%EC%E0%F2%E8%EA%E0/RevModPhys/RevModPhys%201984-2008/root/data/RevModPhys%201984-2008/pdf/RMP/v064/RMP_v064_p0339.pdf
I have refreshed my memory from that article, and I actually think that it confirms what I was saying---decoherence does not change the system from a pure state to a mixed state. To quote from that article:
Although nobody denies the existence and the importance
of decoherence, a criticism has been raised against
its basic significance for the interpretation of quantum
mechanics (Bell, 1975; Zurek, 1982; d'Espagnat, 1990).
Although the reduced density operator becomes diagonal,
the full density operator ρ(t) still represents a pure
state with a permanent superposition, as long as the system
remains isolated. Is it not therefore possible in principle
to perform a very refined measurement upon the environment,
revealing the existence of quantum interferences?
Omnes goes on to say why the pure state is effectively unobservable--there is no way to see interference effects involving the environment, because of the huge number (infinite, in the case of the electromagnetic field) of degrees of freedom of the environment.