Increasing F-A-F Bond Angles: OF2, NF3, CF4, BeF3, BeF2

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The discussion focuses on arranging the bond angles of various AFn species: BeF3, BeF2, CF4, NF3, and OF2. The proposed order of increasing F-A-F bond angles is OF2, NF3, CF4, BeF3, and BeF2, based on the influence of lone pairs on bond angles. OF2 is identified as having the smallest angle due to its bent structure, while BeF2 has the largest angle at 180° due to its linear configuration. Participants emphasize the importance of accurately accounting for the effect of lone pairs on bond angles, which can vary between molecules. The conversation concludes with acknowledgment of the methodology, despite the question being outdated for the original poster.
MysticDude
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Homework Statement


Another chemistry question :D
Arrange the following AFn species in order of increasing F-A-F bond angles: BeF3, BeF2, CF44, NF3, and OF2.

Homework Equations


The Attempt at a Solution


Ok so I'm thinking that it would be OF2 first because it's bent and both of the lone pairs decrease the bond angles by around 2° each, making them 105.5°.

Next should be NF3, the lone pair decreases the bond angle by 2° making it 107.5°.

Then I think that CF4 is next because it would angles around 109.5°.

Next one the list I chose BeF3 because the bond angles would be 120°.

Last I chose BeF2 because it is linear, making the bond angles 180°.

So in the end OF2 -> NF3 -> CF4 -> BeF3 -> BeF2

I hope that you can understand my logic and see if I'm right or wrong. Thanks for any help.
 
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As far as I can see your methodology is correct and you seem to have the right answer. Just be careful and make sure how much the lone pairs decrease the bond angles for each distinct molecule because it can vary, for example 2 degrees for molecule A and 4 degrees for molecule B
 
Okay thanks for the answer. This question is pretty old though and I'm already past the unit in the class.
 

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