- #1
fluidistic
Gold Member
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Homework Statement
There's a step I don't really understand in some "proof".
[itex]d \left ( \frac{\mu }{T} \right )=-\frac{3R du}{2u}-\frac{Rdv}{v}[/itex]. Now he integrates both sides to get [itex]\frac{\mu}{T}- \left ( \frac{\mu}{T} \right ) _0=-\frac{3R}{2} \ln \frac{u}{u_0}-R \ln \frac{v}{v_0}[/itex].
I don't understand how an integration leads to such an expression.